Iron(III) Hydroxide at a glance
| Property | Value |
|---|
| Molar mass | 106.866 g/mol |
|---|
| Molecular weight | 106.866 u |
|---|
| Chemical formula | Fe(OH)3 |
|---|
| Monoisotopic mass | 106.943155 u |
|---|
| CAS number | 1309-33-7 |
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| PubChem CID | 73964 |
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How to calculate the molar mass of iron(III) hydroxide
1 × 55.845 + 3 × 15.999 + 3 × 1.008 = 106.866 g/mol
- Count the atoms in Fe(OH)3: Fe 1, O 3, H 3.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 106.866 g/mol.
Elemental composition of iron(III) hydroxide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Fe Iron | 1 | 55.845 | 55.845 | 52.257% |
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| O Oxygen | 3 | 15.999 | 47.997 | 44.913% |
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| H Hydrogen | 3 | 1.008 | 3.024 | 2.8297% |
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Grams and moles of iron(III) hydroxide
| Amount | Equals |
|---|
| 1 g | 0.0093575 mol |
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| 10 g | 0.093575 mol |
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| 100 g | 0.93575 mol |
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| 0.1 mol | 10.687 g |
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| 1 mol | 106.87 g |
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| 1 g, in particles | 5.6352 × 10^21 |
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Calculate other compounds