Iron(III) Nitrate Nonahydrate at a glance
| Property | Value |
|---|
| Molar mass | 403.992 g/mol |
|---|
| Molecular weight | 403.992 u |
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| Chemical formula | Fe(NO3)3·9H2O |
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| Monoisotopic mass | 403.993472 u |
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| CAS number | 7782-61-8 |
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| PubChem CID | 16211566 |
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How to calculate the molar mass of iron(III) nitrate nonahydrate
1 × 55.845 + 3 × 14.007 + 18 × 15.999 + 18 × 1.008 = 403.992 g/mol
- Count the atoms in Fe(NO3)3·9H2O: Fe 1, N 3, O 18, H 18.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 403.992 g/mol.
Elemental composition of iron(III) nitrate nonahydrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Fe Iron | 1 | 55.845 | 55.845 | 13.823% |
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| N Nitrogen | 3 | 14.007 | 42.021 | 10.401% |
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| O Oxygen | 18 | 15.999 | 287.982 | 71.284% |
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| H Hydrogen | 18 | 1.008 | 18.144 | 4.4912% |
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Grams and moles of iron(III) nitrate nonahydrate
| Amount | Equals |
|---|
| 1 g | 0.0024753 mol |
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| 10 g | 0.024753 mol |
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| 100 g | 0.24753 mol |
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| 0.1 mol | 40.399 g |
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| 1 mol | 403.99 g |
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| 1 g, in particles | 1.4907 × 10^21 |
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