Iron(III) Oxide at a glance
| Property | Value |
|---|
| Molar mass | 159.687 g/mol |
|---|
| Molecular weight | 159.687 u |
|---|
| Chemical formula | Fe2O3 |
|---|
| Monoisotopic mass | 159.854617 u |
|---|
| CAS number | 1309-37-1 |
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| PubChem CID | 518696 |
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How to calculate the molar mass of iron(III) oxide
2 × 55.845 + 3 × 15.999 = 159.687 g/mol
- Count the atoms in Fe2O3: Fe 2, O 3.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 159.687 g/mol.
Elemental composition of iron(III) oxide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Fe Iron | 2 | 55.845 | 111.69 | 69.943% |
|---|
| O Oxygen | 3 | 15.999 | 47.997 | 30.057% |
|---|
Grams and moles of iron(III) oxide
| Amount | Equals |
|---|
| 1 g | 0.0062623 mol |
|---|
| 10 g | 0.062623 mol |
|---|
| 100 g | 0.62623 mol |
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| 0.1 mol | 15.969 g |
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| 1 mol | 159.69 g |
|---|
| 1 g, in particles | 3.7712 × 10^21 |
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