Iron(III) Sulfate at a glance
| Property | Value |
|---|
| Molar mass | 399.858 g/mol |
|---|
| Molecular weight | 399.858 u |
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| Chemical formula | Fe2(SO4)3 |
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| Monoisotopic mass | 399.725062 u |
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| CAS number | 10028-22-5 |
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| PubChem CID | 24826 |
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How to calculate the molar mass of iron(III) sulfate
2 × 55.845 + 3 × 32.06 + 12 × 15.999 = 399.858 g/mol
- Count the atoms in Fe2(SO4)3: Fe 2, S 3, O 12.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 399.858 g/mol.
Elemental composition of iron(III) sulfate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Fe Iron | 2 | 55.845 | 111.69 | 27.932% |
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| S Sulfur | 3 | 32.06 | 96.18 | 24.054% |
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| O Oxygen | 12 | 15.999 | 191.988 | 48.014% |
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Grams and moles of iron(III) sulfate
| Amount | Equals |
|---|
| 1 g | 0.0025009 mol |
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| 10 g | 0.025009 mol |
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| 100 g | 0.25009 mol |
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| 0.1 mol | 39.986 g |
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| 1 mol | 399.86 g |
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| 1 g, in particles | 1.5061 × 10^21 |
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Calculate other compounds