Iron(II) Sulfide at a glance
| Property | Value |
|---|
| Molar mass | 87.905 g/mol |
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| Molecular weight | 87.905 u |
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| Chemical formula | FeS |
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| Monoisotopic mass | 87.9070075 u |
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| CAS number | 1317-37-9 |
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| PubChem CID | 14828 |
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How to calculate the molar mass of iron(II) sulfide
1 × 55.845 + 1 × 32.06 = 87.905 g/mol
- Count the atoms in FeS: Fe 1, S 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 87.905 g/mol.
Elemental composition of iron(II) sulfide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Fe Iron | 1 | 55.845 | 55.845 | 63.529% |
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| S Sulfur | 1 | 32.06 | 32.06 | 36.471% |
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Grams and moles of iron(II) sulfide
| Amount | Equals |
|---|
| 1 g | 0.011376 mol |
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| 10 g | 0.11376 mol |
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| 100 g | 1.1376 mol |
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| 0.1 mol | 8.7905 g |
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| 1 mol | 87.905 g |
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| 1 g, in particles | 6.8507 × 10^21 |
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Calculate other compounds