Iron(II) Sulfate Heptahydrate at a glance
| Property | Value |
|---|
| Molar mass | 278.006 g/mol |
|---|
| Molecular weight | 278.006 u |
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| Chemical formula | FeSO4·7H2O |
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| Monoisotopic mass | 277.960619 u |
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| CAS number | 7782-63-0 |
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| PubChem CID | 62662 |
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How to calculate the molar mass of iron(II) sulfate heptahydrate
1 × 55.845 + 1 × 32.06 + 11 × 15.999 + 14 × 1.008 = 278.006 g/mol
- Count the atoms in FeSO4·7H2O: Fe 1, S 1, O 11, H 14.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 278.006 g/mol.
Elemental composition of iron(II) sulfate heptahydrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Fe Iron | 1 | 55.845 | 55.845 | 20.088% |
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| S Sulfur | 1 | 32.06 | 32.06 | 11.532% |
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| O Oxygen | 11 | 15.999 | 175.989 | 63.304% |
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| H Hydrogen | 14 | 1.008 | 14.112 | 5.0761% |
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Grams and moles of iron(II) sulfate heptahydrate
| Amount | Equals |
|---|
| 1 g | 0.003597 mol |
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| 10 g | 0.03597 mol |
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| 100 g | 0.3597 mol |
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| 0.1 mol | 27.801 g |
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| 1 mol | 278.01 g |
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| 1 g, in particles | 2.1662 × 10^21 |
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