Iron(II) Sulfate at a glance
| Property | Value |
|---|
| Molar mass | 151.901 g/mol |
|---|
| Molecular weight | 151.901 u |
|---|
| Chemical formula | FeSO4 |
|---|
| Monoisotopic mass | 151.886666 u |
|---|
| CAS number | 7720-78-7 |
|---|
| PubChem CID | 24393 |
|---|
How to calculate the molar mass of iron(II) sulfate
1 × 55.845 + 1 × 32.06 + 4 × 15.999 = 151.901 g/mol
- Count the atoms in FeSO4: Fe 1, S 1, O 4.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 151.901 g/mol.
Elemental composition of iron(II) sulfate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Fe Iron | 1 | 55.845 | 55.845 | 36.764% |
|---|
| S Sulfur | 1 | 32.06 | 32.06 | 21.106% |
|---|
| O Oxygen | 4 | 15.999 | 63.996 | 42.13% |
|---|
Grams and moles of iron(II) sulfate
| Amount | Equals |
|---|
| 1 g | 0.0065832 mol |
|---|
| 10 g | 0.065832 mol |
|---|
| 100 g | 0.65832 mol |
|---|
| 0.1 mol | 15.19 g |
|---|
| 1 mol | 151.9 g |
|---|
| 1 g, in particles | 3.9645 × 10^21 |
|---|
Calculate other compounds