Iron(II) Oxide at a glance
| Property | Value |
|---|
| Molar mass | 71.844 g/mol |
|---|
| Molecular weight | 71.844 u |
|---|
| Chemical formula | FeO |
|---|
| Monoisotopic mass | 71.9298509 u |
|---|
| CAS number | 1345-25-1 |
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| PubChem CID | 449809 |
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How to calculate the molar mass of iron(II) oxide
1 × 55.845 + 1 × 15.999 = 71.844 g/mol
- Count the atoms in FeO: Fe 1, O 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 71.844 g/mol.
Elemental composition of iron(II) oxide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Fe Iron | 1 | 55.845 | 55.845 | 77.731% |
|---|
| O Oxygen | 1 | 15.999 | 15.999 | 22.269% |
|---|
Grams and moles of iron(II) oxide
| Amount | Equals |
|---|
| 1 g | 0.013919 mol |
|---|
| 10 g | 0.13919 mol |
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| 100 g | 1.3919 mol |
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| 0.1 mol | 7.1844 g |
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| 1 mol | 71.844 g |
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| 1 g, in particles | 8.3822 × 10^21 |
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Calculate other compounds