Iron(II,III) Oxide at a glance
| Property | Value |
|---|
| Molar mass | 231.531 g/mol |
|---|
| Molecular weight | 231.531 u |
|---|
| Chemical formula | Fe3O4 |
|---|
| Monoisotopic mass | 231.784467 u |
|---|
| CAS number | 1317-61-9 |
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| PubChem CID | 16211978 |
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How to calculate the molar mass of iron(II,III) oxide
3 × 55.845 + 4 × 15.999 = 231.531 g/mol
- Count the atoms in Fe3O4: Fe 3, O 4.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 231.531 g/mol.
Elemental composition of iron(II,III) oxide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Fe Iron | 3 | 55.845 | 167.535 | 72.36% |
|---|
| O Oxygen | 4 | 15.999 | 63.996 | 27.64% |
|---|
Grams and moles of iron(II,III) oxide
| Amount | Equals |
|---|
| 1 g | 0.0043191 mol |
|---|
| 10 g | 0.043191 mol |
|---|
| 100 g | 0.43191 mol |
|---|
| 0.1 mol | 23.153 g |
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| 1 mol | 231.53 g |
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| 1 g, in particles | 2.601 × 10^21 |
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Calculate other compounds