Barium Nitrate at a glance
| Property | Value |
|---|
| Molar mass | 261.338 g/mol |
|---|
| Molecular weight | 261.338 u |
|---|
| Chemical formula | Ba(NO3)2 |
|---|
| CAS number | 10022-31-8 |
|---|
| PubChem CID | 24798 |
|---|
How to calculate the molar mass of barium nitrate
1 × 137.33 + 2 × 14.007 + 6 × 15.999 = 261.338 g/mol
- Count the atoms in Ba(NO3)2: Ba 1, N 2, O 6.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 261.338 g/mol.
Elemental composition of barium nitrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Ba Barium | 1 | 137.33 | 137.33 | 52.549% |
|---|
| N Nitrogen | 2 | 14.007 | 28.014 | 10.719% |
|---|
| O Oxygen | 6 | 15.999 | 95.994 | 36.732% |
|---|
Grams and moles of barium nitrate
| Amount | Equals |
|---|
| 1 g | 0.0038265 mol |
|---|
| 10 g | 0.038265 mol |
|---|
| 100 g | 0.38265 mol |
|---|
| 0.1 mol | 26.134 g |
|---|
| 1 mol | 261.34 g |
|---|
| 1 g, in particles | 2.3043 × 10^21 |
|---|
Calculate other compounds