Barium Oxide at a glance
| Property | Value |
|---|
| Molar mass | 153.329 g/mol |
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| Molecular weight | 153.329 u |
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| Chemical formula | BaO |
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| CAS number | 1304-28-5 |
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| PubChem CID | 62392 |
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How to calculate the molar mass of barium oxide
1 × 137.33 + 1 × 15.999 = 153.329 g/mol
- Count the atoms in BaO: Ba 1, O 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 153.329 g/mol.
Elemental composition of barium oxide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Ba Barium | 1 | 137.33 | 137.33 | 89.566% |
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| O Oxygen | 1 | 15.999 | 15.999 | 10.434% |
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Grams and moles of barium oxide
| Amount | Equals |
|---|
| 1 g | 0.0065219 mol |
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| 10 g | 0.065219 mol |
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| 100 g | 0.65219 mol |
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| 0.1 mol | 15.333 g |
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| 1 mol | 153.33 g |
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| 1 g, in particles | 3.9276 × 10^21 |
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Calculate other compounds