Barium Sulfate at a glance
| Property | Value |
|---|
| Molar mass | 233.386 g/mol |
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| Molecular weight | 233.386 u |
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| Chemical formula | BaSO4 |
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| CAS number | 7727-43-7 |
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| PubChem CID | 24414 |
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How to calculate the molar mass of barium sulfate
1 × 137.33 + 1 × 32.06 + 4 × 15.999 = 233.386 g/mol
- Count the atoms in BaSO4: Ba 1, S 1, O 4.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 233.386 g/mol.
Elemental composition of barium sulfate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Ba Barium | 1 | 137.33 | 137.33 | 58.842% |
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| S Sulfur | 1 | 32.06 | 32.06 | 13.737% |
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| O Oxygen | 4 | 15.999 | 63.996 | 27.421% |
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Grams and moles of barium sulfate
| Amount | Equals |
|---|
| 1 g | 0.0042847 mol |
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| 10 g | 0.042847 mol |
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| 100 g | 0.42847 mol |
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| 0.1 mol | 23.339 g |
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| 1 mol | 233.39 g |
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| 1 g, in particles | 2.5803 × 10^21 |
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Calculate other compounds