Barium Hydroxide at a glance
| Property | Value |
|---|
| Molar mass | 171.344 g/mol |
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| Molecular weight | 171.344 u |
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| Chemical formula | Ba(OH)2 |
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| CAS number | 17194-00-2 |
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| PubChem CID | 6093286 |
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How to calculate the molar mass of barium hydroxide
1 × 137.33 + 2 × 15.999 + 2 × 1.008 = 171.344 g/mol
- Count the atoms in Ba(OH)2: Ba 1, O 2, H 2.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 171.344 g/mol.
Elemental composition of barium hydroxide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Ba Barium | 1 | 137.33 | 137.33 | 80.149% |
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| O Oxygen | 2 | 15.999 | 31.998 | 18.675% |
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| H Hydrogen | 2 | 1.008 | 2.016 | 1.1766% |
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Grams and moles of barium hydroxide
| Amount | Equals |
|---|
| 1 g | 0.0058362 mol |
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| 10 g | 0.058362 mol |
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| 100 g | 0.58362 mol |
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| 0.1 mol | 17.134 g |
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| 1 mol | 171.34 g |
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| 1 g, in particles | 3.5146 × 10^21 |
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Calculate other compounds