Barium Chloride Dihydrate at a glance
| Property | Value |
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| Molar mass | 244.26 g/mol |
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| Molecular weight | 244.26 u |
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| Chemical formula | BaCl2·2H2O |
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| CAS number | 10326-27-9 |
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| PubChem CID | 5284346 |
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How to calculate the molar mass of barium chloride dihydrate
1 × 137.33 + 2 × 35.45 + 4 × 1.008 + 2 × 15.999 = 244.26 g/mol
- Count the atoms in BaCl2·2H2O: Ba 1, Cl 2, H 4, O 2.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 244.26 g/mol.
Elemental composition of barium chloride dihydrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
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| Ba Barium | 1 | 137.33 | 137.33 | 56.223% |
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| Cl Chlorine | 2 | 35.45 | 70.9 | 29.026% |
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| H Hydrogen | 4 | 1.008 | 4.032 | 1.6507% |
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| O Oxygen | 2 | 15.999 | 31.998 | 13.1% |
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Grams and moles of barium chloride dihydrate
| Amount | Equals |
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| 1 g | 0.004094 mol |
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| 10 g | 0.04094 mol |
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| 100 g | 0.4094 mol |
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| 0.1 mol | 24.426 g |
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| 1 mol | 244.26 g |
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| 1 g, in particles | 2.4655 × 10^21 |
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