Tetramethylethylenediamine at a glance
| Property | Value |
|---|
| Molar mass | 116.208 g/mol |
|---|
| Molecular weight | 116.208 u |
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| Chemical formula | C6H16N2 |
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| Monoisotopic mass | 116.131349 u |
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| CAS number | 110-18-9 |
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| PubChem CID | 8037 |
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How to calculate the molar mass of tetramethylethylenediamine
6 × 12.011 + 16 × 1.008 + 2 × 14.007 = 116.208 g/mol
- Count the atoms in C6H16N2: C 6, H 16, N 2.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 116.208 g/mol.
Elemental composition of tetramethylethylenediamine
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 6 | 12.011 | 72.066 | 62.015% |
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| H Hydrogen | 16 | 1.008 | 16.128 | 13.879% |
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| N Nitrogen | 2 | 14.007 | 28.014 | 24.107% |
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Grams and moles of tetramethylethylenediamine
| Amount | Equals |
|---|
| 1 g | 0.0086053 mol |
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| 10 g | 0.086053 mol |
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| 100 g | 0.86053 mol |
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| 0.1 mol | 11.621 g |
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| 1 mol | 116.21 g |
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| 1 g, in particles | 5.1822 × 10^21 |
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