Tetrahydrocannabinol at a glance
| Property | Value |
|---|
| Molar mass | 314.469 g/mol |
|---|
| Molecular weight | 314.469 u |
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| Chemical formula | C21H30O2 |
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| Monoisotopic mass | 314.22458 u |
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| CAS number | 1972-08-3 |
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| PubChem CID | 16078 |
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How to calculate the molar mass of tetrahydrocannabinol
21 × 12.011 + 30 × 1.008 + 2 × 15.999 = 314.469 g/mol
- Count the atoms in C21H30O2: C 21, H 30, O 2.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 314.469 g/mol.
Elemental composition of tetrahydrocannabinol
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 21 | 12.011 | 252.231 | 80.209% |
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| H Hydrogen | 30 | 1.008 | 30.24 | 9.6162% |
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| O Oxygen | 2 | 15.999 | 31.998 | 10.175% |
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Grams and moles of tetrahydrocannabinol
| Amount | Equals |
|---|
| 1 g | 0.00318 mol |
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| 10 g | 0.0318 mol |
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| 100 g | 0.318 mol |
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| 0.1 mol | 31.447 g |
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| 1 mol | 314.47 g |
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| 1 g, in particles | 1.915 × 10^21 |
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Calculate other compounds