Lisinopril at a glance
| Property | Value |
|---|
| Molar mass | 405.495 g/mol |
|---|
| Molecular weight | 405.495 u |
|---|
| Chemical formula | C21H31N3O5 |
|---|
| Monoisotopic mass | 405.226371 u |
|---|
| CAS number | 76547-98-3 |
|---|
| PubChem CID | 5362119 |
|---|
How to calculate the molar mass of lisinopril
21 × 12.011 + 31 × 1.008 + 3 × 14.007 + 5 × 15.999 = 405.495 g/mol
- Count the atoms in C21H31N3O5: C 21, H 31, N 3, O 5.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 405.495 g/mol.
Elemental composition of lisinopril
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 21 | 12.011 | 252.231 | 62.203% |
|---|
| H Hydrogen | 31 | 1.008 | 31.248 | 7.7061% |
|---|
| N Nitrogen | 3 | 14.007 | 42.021 | 10.363% |
|---|
| O Oxygen | 5 | 15.999 | 79.995 | 19.728% |
|---|
Grams and moles of lisinopril
| Amount | Equals |
|---|
| 1 g | 0.0024661 mol |
|---|
| 10 g | 0.024661 mol |
|---|
| 100 g | 0.24661 mol |
|---|
| 0.1 mol | 40.55 g |
|---|
| 1 mol | 405.5 g |
|---|
| 1 g, in particles | 1.4851 × 10^21 |
|---|
Calculate other compounds