Lidocaine at a glance
| Property | Value |
|---|
| Molar mass | 234.343 g/mol |
|---|
| Molecular weight | 234.343 u |
|---|
| Chemical formula | C14H22N2O |
|---|
| Monoisotopic mass | 234.173213 u |
|---|
| CAS number | 137-58-6 |
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| PubChem CID | 3676 |
|---|
How to calculate the molar mass of lidocaine
14 × 12.011 + 22 × 1.008 + 2 × 14.007 + 1 × 15.999 = 234.343 g/mol
- Count the atoms in C14H22N2O: C 14, H 22, N 2, O 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 234.343 g/mol.
Elemental composition of lidocaine
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 14 | 12.011 | 168.154 | 71.756% |
|---|
| H Hydrogen | 22 | 1.008 | 22.176 | 9.4631% |
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| N Nitrogen | 2 | 14.007 | 28.014 | 11.954% |
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| O Oxygen | 1 | 15.999 | 15.999 | 6.8272% |
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Grams and moles of lidocaine
| Amount | Equals |
|---|
| 1 g | 0.0042672 mol |
|---|
| 10 g | 0.042672 mol |
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| 100 g | 0.42672 mol |
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| 0.1 mol | 23.434 g |
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| 1 mol | 234.34 g |
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| 1 g, in particles | 2.5698 × 10^21 |
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Calculate other compounds