Levodopa at a glance
| Property | Value |
|---|
| Molar mass | 197.19 g/mol |
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| Molecular weight | 197.19 u |
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| Chemical formula | C9H11NO4 |
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| Monoisotopic mass | 197.068808 u |
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| CAS number | 59-92-7 |
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| PubChem CID | 6047 |
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How to calculate the molar mass of levodopa
9 × 12.011 + 11 × 1.008 + 1 × 14.007 + 4 × 15.999 = 197.19 g/mol
- Count the atoms in C9H11NO4: C 9, H 11, N 1, O 4.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 197.19 g/mol.
Elemental composition of levodopa
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 9 | 12.011 | 108.099 | 54.82% |
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| H Hydrogen | 11 | 1.008 | 11.088 | 5.623% |
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| N Nitrogen | 1 | 14.007 | 14.007 | 7.1033% |
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| O Oxygen | 4 | 15.999 | 63.996 | 32.454% |
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Grams and moles of levodopa
| Amount | Equals |
|---|
| 1 g | 0.0050713 mol |
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| 10 g | 0.050713 mol |
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| 100 g | 0.50713 mol |
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| 0.1 mol | 19.719 g |
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| 1 mol | 197.19 g |
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| 1 g, in particles | 3.054 × 10^21 |
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Calculate other compounds