Lead(IV) Oxide at a glance
| Property | Value |
|---|
| Molar mass | 238.998 g/mol |
|---|
| Molecular weight | 238.998 u |
|---|
| Chemical formula | PbO2 |
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| CAS number | 1309-60-0 |
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| PubChem CID | 14793 |
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How to calculate the molar mass of lead(IV) oxide
1 × 207 + 2 × 15.999 = 238.998 g/mol
- Count the atoms in PbO2: Pb 1, O 2.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 238.998 g/mol.
Elemental composition of lead(IV) oxide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Pb Lead | 1 | 207 | 207 | 86.612% |
|---|
| O Oxygen | 2 | 15.999 | 31.998 | 13.388% |
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Grams and moles of lead(IV) oxide
| Amount | Equals |
|---|
| 1 g | 0.0041841 mol |
|---|
| 10 g | 0.041841 mol |
|---|
| 100 g | 0.41841 mol |
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| 0.1 mol | 23.9 g |
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| 1 mol | 239 g |
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| 1 g, in particles | 2.5197 × 10^21 |
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Calculate other compounds