Lithium Aluminum Hydride at a glance
| Property | Value |
|---|
| Molar mass | 37.954 g/mol |
|---|
| Molecular weight | 37.954 u |
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| Chemical formula | LiAlH4 |
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| Monoisotopic mass | 38.0288421 u |
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| CAS number | 16853-85-3 |
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| PubChem CID | 28112 |
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How to calculate the molar mass of lithium aluminum hydride
1 × 6.94 + 1 × 26.982 + 4 × 1.008 = 37.954 g/mol
- Count the atoms in LiAlH4: Li 1, Al 1, H 4.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 37.954 g/mol.
Elemental composition of lithium aluminum hydride
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Li Lithium | 1 | 6.94 | 6.94 | 18.285% |
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| Al Aluminum | 1 | 26.982 | 26.982 | 71.091% |
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| H Hydrogen | 4 | 1.008 | 4.032 | 10.623% |
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Grams and moles of lithium aluminum hydride
| Amount | Equals |
|---|
| 1 g | 0.026348 mol |
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| 10 g | 0.26348 mol |
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| 100 g | 2.6348 mol |
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| 0.1 mol | 3.7954 g |
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| 1 mol | 37.954 g |
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| 1 g, in particles | 1.5867 × 10^22 |
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Calculate other compounds