Disodium EDTA Dihydrate at a glance
| Property | Value |
|---|
| Molar mass | 372.238 g/mol |
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| Molecular weight | 372.238 u |
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| Chemical formula | C10H14N2Na2O8·2H2O |
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| Monoisotopic mass | 372.075683 u |
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| PubChem CID | 636371 |
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How to calculate the molar mass of disodium EDTA dihydrate
10 × 12.011 + 18 × 1.008 + 2 × 14.007 + 2 × 22.99 + 10 × 15.999 = 372.238 g/mol
- Count the atoms in C10H14N2Na2O8·2H2O: C 10, H 18, N 2, Na 2, O 10.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 372.238 g/mol.
Elemental composition of disodium EDTA dihydrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 10 | 12.011 | 120.11 | 32.267% |
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| H Hydrogen | 18 | 1.008 | 18.144 | 4.8743% |
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| N Nitrogen | 2 | 14.007 | 28.014 | 7.5258% |
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| Na Sodium | 2 | 22.99 | 45.98 | 12.352% |
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| O Oxygen | 10 | 15.999 | 159.99 | 42.981% |
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Grams and moles of disodium EDTA dihydrate
| Amount | Equals |
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| 1 g | 0.0026865 mol |
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| 10 g | 0.026865 mol |
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| 100 g | 0.26865 mol |
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| 0.1 mol | 37.224 g |
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| 1 mol | 372.24 g |
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| 1 g, in particles | 1.6178 × 10^21 |
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