Diphenhydramine at a glance
| Property | Value |
|---|
| Molar mass | 255.361 g/mol |
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| Molecular weight | 255.361 u |
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| Chemical formula | C17H21NO |
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| Monoisotopic mass | 255.162314 u |
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| CAS number | 58-73-1 |
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| PubChem CID | 3100 |
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How to calculate the molar mass of diphenhydramine
17 × 12.011 + 21 × 1.008 + 1 × 14.007 + 1 × 15.999 = 255.361 g/mol
- Count the atoms in C17H21NO: C 17, H 21, N 1, O 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 255.361 g/mol.
Elemental composition of diphenhydramine
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 17 | 12.011 | 204.187 | 79.96% |
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| H Hydrogen | 21 | 1.008 | 21.168 | 8.2894% |
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| N Nitrogen | 1 | 14.007 | 14.007 | 5.4852% |
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| O Oxygen | 1 | 15.999 | 15.999 | 6.2652% |
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Grams and moles of diphenhydramine
| Amount | Equals |
|---|
| 1 g | 0.003916 mol |
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| 10 g | 0.03916 mol |
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| 100 g | 0.3916 mol |
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| 0.1 mol | 25.536 g |
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| 1 mol | 255.36 g |
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| 1 g, in particles | 2.3583 × 10^21 |
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Calculate other compounds