Dinitrogen Tetroxide at a glance
| Property | Value |
|---|
| Molar mass | 92.01 g/mol |
|---|
| Molecular weight | 92.01 u |
|---|
| Chemical formula | N2O4 |
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| Monoisotopic mass | 91.9858065 u |
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| CAS number | 10544-72-6 |
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| PubChem CID | 25352 |
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How to calculate the molar mass of dinitrogen tetroxide
2 × 14.007 + 4 × 15.999 = 92.01 g/mol
- Count the atoms in N2O4: N 2, O 4.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 92.01 g/mol.
Elemental composition of dinitrogen tetroxide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| N Nitrogen | 2 | 14.007 | 28.014 | 30.447% |
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| O Oxygen | 4 | 15.999 | 63.996 | 69.553% |
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Grams and moles of dinitrogen tetroxide
| Amount | Equals |
|---|
| 1 g | 0.010868 mol |
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| 10 g | 0.10868 mol |
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| 100 g | 1.0868 mol |
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| 0.1 mol | 9.201 g |
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| 1 mol | 92.01 g |
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| 1 g, in particles | 6.5451 × 10^21 |
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