Trisodium Citrate Dihydrate at a glance
| Property | Value |
|---|
| Molar mass | 294.099 g/mol |
|---|
| Molecular weight | 294.099 u |
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| Chemical formula | Na3C6H5O7·2H2O |
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| Monoisotopic mass | 293.993965 u |
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| CAS number | 6132-04-3 |
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| PubChem CID | 71474 |
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How to calculate the molar mass of trisodium citrate dihydrate
3 × 22.99 + 6 × 12.011 + 9 × 1.008 + 9 × 15.999 = 294.099 g/mol
- Count the atoms in Na3C6H5O7·2H2O: Na 3, C 6, H 9, O 9.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 294.099 g/mol.
Elemental composition of trisodium citrate dihydrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Na Sodium | 3 | 22.99 | 68.97 | 23.451% |
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| C Carbon | 6 | 12.011 | 72.066 | 24.504% |
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| H Hydrogen | 9 | 1.008 | 9.072 | 3.0847% |
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| O Oxygen | 9 | 15.999 | 143.991 | 48.96% |
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Grams and moles of trisodium citrate dihydrate
| Amount | Equals |
|---|
| 1 g | 0.0034002 mol |
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| 10 g | 0.034002 mol |
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| 100 g | 0.34002 mol |
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| 0.1 mol | 29.41 g |
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| 1 mol | 294.1 g |
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| 1 g, in particles | 2.0477 × 10^21 |
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