Trisodium Citrate at a glance
| Property | Value |
|---|
| Molar mass | 258.069 g/mol |
|---|
| Molecular weight | 258.069 u |
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| Chemical formula | Na3C6H5O7 |
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| Monoisotopic mass | 257.972835 u |
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| CAS number | 68-04-2 |
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| PubChem CID | 6224 |
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How to calculate the molar mass of trisodium citrate
3 × 22.99 + 6 × 12.011 + 5 × 1.008 + 7 × 15.999 = 258.069 g/mol
- Count the atoms in Na3C6H5O7: Na 3, C 6, H 5, O 7.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 258.069 g/mol.
Elemental composition of trisodium citrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Na Sodium | 3 | 22.99 | 68.97 | 26.725% |
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| C Carbon | 6 | 12.011 | 72.066 | 27.925% |
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| H Hydrogen | 5 | 1.008 | 5.04 | 1.953% |
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| O Oxygen | 7 | 15.999 | 111.993 | 43.397% |
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Grams and moles of trisodium citrate
| Amount | Equals |
|---|
| 1 g | 0.0038749 mol |
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| 10 g | 0.038749 mol |
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| 100 g | 0.38749 mol |
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| 0.1 mol | 25.807 g |
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| 1 mol | 258.07 g |
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| 1 g, in particles | 2.3335 × 10^21 |
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