Sodium Bromide at a glance
| Property | Value |
|---|
| Molar mass | 102.894 g/mol |
|---|
| Molecular weight | 102.894 u |
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| Chemical formula | NaBr |
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| Monoisotopic mass | 101.908107 u |
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| CAS number | 7647-15-6 |
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| PubChem CID | 253881 |
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How to calculate the molar mass of sodium bromide
1 × 22.99 + 1 × 79.904 = 102.894 g/mol
- Count the atoms in NaBr: Na 1, Br 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 102.894 g/mol.
Elemental composition of sodium bromide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Na Sodium | 1 | 22.99 | 22.99 | 22.343% |
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| Br Bromine | 1 | 79.904 | 79.904 | 77.657% |
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Grams and moles of sodium bromide
| Amount | Equals |
|---|
| 1 g | 0.0097187 mol |
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| 10 g | 0.097187 mol |
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| 100 g | 0.97187 mol |
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| 0.1 mol | 10.289 g |
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| 1 mol | 102.89 g |
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| 1 g, in particles | 5.8528 × 10^21 |
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Calculate other compounds