Sodium Borohydride at a glance
| Property | Value |
|---|
| Molar mass | 37.832 g/mol |
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| Molecular weight | 37.832 u |
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| Chemical formula | NaBH4 |
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| Monoisotopic mass | 38.0303748 u |
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| CAS number | 16940-66-2 |
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| PubChem CID | 4311764 |
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How to calculate the molar mass of sodium borohydride
1 × 22.99 + 1 × 10.81 + 4 × 1.008 = 37.832 g/mol
- Count the atoms in NaBH4: Na 1, B 1, H 4.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 37.832 g/mol.
Elemental composition of sodium borohydride
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
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| Na Sodium | 1 | 22.99 | 22.99 | 60.769% |
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| B Boron | 1 | 10.81 | 10.81 | 28.574% |
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| H Hydrogen | 4 | 1.008 | 4.032 | 10.658% |
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Grams and moles of sodium borohydride
| Amount | Equals |
|---|
| 1 g | 0.026433 mol |
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| 10 g | 0.26433 mol |
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| 100 g | 2.6433 mol |
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| 0.1 mol | 3.7832 g |
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| 1 mol | 37.832 g |
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| 1 g, in particles | 1.5918 × 10^22 |
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Calculate other compounds