Loratadine at a glance
| Property | Value |
|---|
| Molar mass | 382.888 g/mol |
|---|
| Molecular weight | 382.888 u |
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| Chemical formula | C22H23ClN2O2 |
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| Monoisotopic mass | 382.144806 u |
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| CAS number | 79794-75-5 |
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| PubChem CID | 3957 |
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How to calculate the molar mass of loratadine
22 × 12.011 + 23 × 1.008 + 1 × 35.45 + 2 × 14.007 + 2 × 15.999 = 382.888 g/mol
- Count the atoms in C22H23ClN2O2: C 22, H 23, Cl 1, N 2, O 2.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 382.888 g/mol.
Elemental composition of loratadine
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 22 | 12.011 | 264.242 | 69.013% |
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| H Hydrogen | 23 | 1.008 | 23.184 | 6.055% |
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| Cl Chlorine | 1 | 35.45 | 35.45 | 9.2586% |
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| N Nitrogen | 2 | 14.007 | 28.014 | 7.3165% |
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| O Oxygen | 2 | 15.999 | 31.998 | 8.357% |
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Grams and moles of loratadine
| Amount | Equals |
|---|
| 1 g | 0.0026117 mol |
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| 10 g | 0.026117 mol |
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| 100 g | 0.26117 mol |
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| 0.1 mol | 38.289 g |
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| 1 mol | 382.89 g |
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| 1 g, in particles | 1.5728 × 10^21 |
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