Lithium Fluoride at a glance
| Property | Value |
|---|
| Molar mass | 25.938 g/mol |
|---|
| Molecular weight | 25.938 u |
|---|
| Chemical formula | LiF |
|---|
| Monoisotopic mass | 26.0144066 u |
|---|
| CAS number | 7789-24-4 |
|---|
| PubChem CID | 224478 |
|---|
How to calculate the molar mass of lithium fluoride
1 × 6.94 + 1 × 18.998 = 25.938 g/mol
- Count the atoms in LiF: Li 1, F 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 25.938 g/mol.
Elemental composition of lithium fluoride
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Li Lithium | 1 | 6.94 | 6.94 | 26.756% |
|---|
| F Fluorine | 1 | 18.998 | 18.998 | 73.244% |
|---|
Grams and moles of lithium fluoride
| Amount | Equals |
|---|
| 1 g | 0.038553 mol |
|---|
| 10 g | 0.38553 mol |
|---|
| 100 g | 3.8553 mol |
|---|
| 0.1 mol | 2.5938 g |
|---|
| 1 mol | 25.938 g |
|---|
| 1 g, in particles | 2.3217 × 10^22 |
|---|
Calculate other compounds