Cetirizine at a glance
| Property | Value |
|---|
| Molar mass | 388.892 g/mol |
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| Molecular weight | 388.892 u |
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| Chemical formula | C21H25ClN2O3 |
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| Monoisotopic mass | 388.15537 u |
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| CAS number | 83881-51-0 |
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| PubChem CID | 2678 |
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How to calculate the molar mass of cetirizine
21 × 12.011 + 25 × 1.008 + 1 × 35.45 + 2 × 14.007 + 3 × 15.999 = 388.892 g/mol
- Count the atoms in C21H25ClN2O3: C 21, H 25, Cl 1, N 2, O 3.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 388.892 g/mol.
Elemental composition of cetirizine
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 21 | 12.011 | 252.231 | 64.859% |
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| H Hydrogen | 25 | 1.008 | 25.2 | 6.4799% |
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| Cl Chlorine | 1 | 35.45 | 35.45 | 9.1156% |
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| N Nitrogen | 2 | 14.007 | 28.014 | 7.2035% |
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| O Oxygen | 3 | 15.999 | 47.997 | 12.342% |
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Grams and moles of cetirizine
| Amount | Equals |
|---|
| 1 g | 0.0025714 mol |
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| 10 g | 0.025714 mol |
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| 100 g | 0.25714 mol |
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| 0.1 mol | 38.889 g |
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| 1 mol | 388.89 g |
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| 1 g, in particles | 1.5485 × 10^21 |
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Calculate other compounds