Catechol at a glance
| Property | Value |
|---|
| Molar mass | 110.112 g/mol |
|---|
| Molecular weight | 110.112 u |
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| Chemical formula | C6H6O2 |
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| Monoisotopic mass | 110.036779 u |
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| CAS number | 120-80-9 |
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| PubChem CID | 289 |
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How to calculate the molar mass of catechol
6 × 12.011 + 6 × 1.008 + 2 × 15.999 = 110.112 g/mol
- Count the atoms in C6H6O2: C 6, H 6, O 2.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 110.112 g/mol.
Elemental composition of catechol
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 6 | 12.011 | 72.066 | 65.448% |
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| H Hydrogen | 6 | 1.008 | 6.048 | 5.4926% |
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| O Oxygen | 2 | 15.999 | 31.998 | 29.06% |
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Grams and moles of catechol
| Amount | Equals |
|---|
| 1 g | 0.0090817 mol |
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| 10 g | 0.090817 mol |
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| 100 g | 0.90817 mol |
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| 0.1 mol | 11.011 g |
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| 1 mol | 110.11 g |
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| 1 g, in particles | 5.4691 × 10^21 |
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Calculate other compounds