Ammonium Nitrate at a glance
| Property | Value |
|---|
| Molar mass | 80.043 g/mol |
|---|
| Molecular weight | 80.043 u |
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| Chemical formula | NH4NO3 |
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| Monoisotopic mass | 80.022192 u |
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| CAS number | 6484-52-2 |
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| PubChem CID | 22985 |
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How to calculate the molar mass of ammonium nitrate
2 × 14.007 + 4 × 1.008 + 3 × 15.999 = 80.043 g/mol
- Count the atoms in NH4NO3: N 2, H 4, O 3.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 80.043 g/mol.
Elemental composition of ammonium nitrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| N Nitrogen | 2 | 14.007 | 28.014 | 34.999% |
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| H Hydrogen | 4 | 1.008 | 4.032 | 5.0373% |
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| O Oxygen | 3 | 15.999 | 47.997 | 59.964% |
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Grams and moles of ammonium nitrate
| Amount | Equals |
|---|
| 1 g | 0.012493 mol |
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| 10 g | 0.12493 mol |
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| 100 g | 1.2493 mol |
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| 0.1 mol | 8.0043 g |
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| 1 mol | 80.043 g |
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| 1 g, in particles | 7.5236 × 10^21 |
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Calculate other compounds