Ammonium Iron(II) Sulfate Hexahydrate at a glance
| Property | Value |
|---|
| Molar mass | 392.125 g/mol |
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| Molecular weight | 392.125 u |
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| Chemical formula | (NH4)2Fe(SO4)2·6H2O |
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| Monoisotopic mass | 391.970532 u |
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| PubChem CID | 15942308 |
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How to calculate the molar mass of ammonium iron(II) sulfate hexahydrate
2 × 14.007 + 20 × 1.008 + 1 × 55.845 + 2 × 32.06 + 14 × 15.999 = 392.125 g/mol
- Count the atoms in (NH4)2Fe(SO4)2·6H2O: N 2, H 20, Fe 1, S 2, O 14.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 392.125 g/mol.
Elemental composition of ammonium iron(II) sulfate hexahydrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| N Nitrogen | 2 | 14.007 | 28.014 | 7.1442% |
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| H Hydrogen | 20 | 1.008 | 20.16 | 5.1412% |
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| Fe Iron | 1 | 55.845 | 55.845 | 14.242% |
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| S Sulfur | 2 | 32.06 | 64.12 | 16.352% |
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| O Oxygen | 14 | 15.999 | 223.986 | 57.121% |
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Grams and moles of ammonium iron(II) sulfate hexahydrate
| Amount | Equals |
|---|
| 1 g | 0.0025502 mol |
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| 10 g | 0.025502 mol |
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| 100 g | 0.25502 mol |
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| 0.1 mol | 39.213 g |
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| 1 mol | 392.13 g |
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| 1 g, in particles | 1.5358 × 10^21 |
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