Acrylamide at a glance
| Property | Value |
|---|
| Molar mass | 71.079 g/mol |
|---|
| Molecular weight | 71.079 u |
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| Chemical formula | C3H5NO |
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| Monoisotopic mass | 71.0371138 u |
|---|
| CAS number | 79-06-1 |
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| PubChem CID | 6579 |
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How to calculate the molar mass of acrylamide
3 × 12.011 + 5 × 1.008 + 1 × 14.007 + 1 × 15.999 = 71.079 g/mol
- Count the atoms in C3H5NO: C 3, H 5, N 1, O 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 71.079 g/mol.
Elemental composition of acrylamide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 3 | 12.011 | 36.033 | 50.694% |
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| H Hydrogen | 5 | 1.008 | 5.04 | 7.0907% |
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| N Nitrogen | 1 | 14.007 | 14.007 | 19.706% |
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| O Oxygen | 1 | 15.999 | 15.999 | 22.509% |
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Grams and moles of acrylamide
| Amount | Equals |
|---|
| 1 g | 0.014069 mol |
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| 10 g | 0.14069 mol |
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| 100 g | 1.4069 mol |
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| 0.1 mol | 7.1079 g |
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| 1 mol | 71.079 g |
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| 1 g, in particles | 8.4725 × 10^21 |
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Calculate other compounds