Acetaminophen at a glance
| Property | Value |
|---|
| Molar mass | 151.165 g/mol |
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| Molecular weight | 151.165 u |
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| Chemical formula | C8H9NO2 |
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| Monoisotopic mass | 151.063329 u |
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| CAS number | 103-90-2 |
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| PubChem CID | 1983 |
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How to calculate the molar mass of acetaminophen
8 × 12.011 + 9 × 1.008 + 1 × 14.007 + 2 × 15.999 = 151.165 g/mol
- Count the atoms in C8H9NO2: C 8, H 9, N 1, O 2.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 151.165 g/mol.
Elemental composition of acetaminophen
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 8 | 12.011 | 96.088 | 63.565% |
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| H Hydrogen | 9 | 1.008 | 9.072 | 6.0014% |
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| N Nitrogen | 1 | 14.007 | 14.007 | 9.266% |
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| O Oxygen | 2 | 15.999 | 31.998 | 21.168% |
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Grams and moles of acetaminophen
| Amount | Equals |
|---|
| 1 g | 0.0066153 mol |
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| 10 g | 0.066153 mol |
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| 100 g | 0.66153 mol |
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| 0.1 mol | 15.117 g |
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| 1 mol | 151.17 g |
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| 1 g, in particles | 3.9838 × 10^21 |
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Calculate other compounds