Acetaldehyde at a glance
| Property | Value |
|---|
| Molar mass | 44.053 g/mol |
|---|
| Molecular weight | 44.053 u |
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| Chemical formula | CH3CHO |
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| Monoisotopic mass | 44.0262147 u |
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| CAS number | 75-07-0 |
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| PubChem CID | 177 |
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How to calculate the molar mass of acetaldehyde
2 × 12.011 + 4 × 1.008 + 1 × 15.999 = 44.053 g/mol
- Count the atoms in CH3CHO: C 2, H 4, O 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 44.053 g/mol.
Elemental composition of acetaldehyde
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 2 | 12.011 | 24.022 | 54.53% |
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| H Hydrogen | 4 | 1.008 | 4.032 | 9.1526% |
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| O Oxygen | 1 | 15.999 | 15.999 | 36.318% |
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Grams and moles of acetaldehyde
| Amount | Equals |
|---|
| 1 g | 0.0227 mol |
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| 10 g | 0.227 mol |
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| 100 g | 2.27 mol |
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| 0.1 mol | 4.4053 g |
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| 1 mol | 44.053 g |
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| 1 g, in particles | 1.367 × 10^22 |
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Calculate other compounds