Vanadium Pentoxide at a glance
| Property | Value |
|---|
| Molar mass | 181.878 g/mol |
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| Molecular weight | 181.878 u |
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| Chemical formula | V2O5 |
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| CAS number | 1314-62-1 |
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| PubChem CID | 14814 |
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How to calculate the molar mass of vanadium pentoxide
2 × 50.9415 + 5 × 15.999 = 181.878 g/mol
- Count the atoms in V2O5: V 2, O 5.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 181.878 g/mol.
Elemental composition of vanadium pentoxide
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| V Vanadium | 2 | 50.9415 | 101.883 | 56.017% |
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| O Oxygen | 5 | 15.999 | 79.995 | 43.983% |
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Grams and moles of vanadium pentoxide
| Amount | Equals |
|---|
| 1 g | 0.0054982 mol |
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| 10 g | 0.054982 mol |
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| 100 g | 0.54982 mol |
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| 0.1 mol | 18.188 g |
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| 1 mol | 181.88 g |
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| 1 g, in particles | 3.3111 × 10^21 |
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