Triethylamine at a glance
| Property | Value |
|---|
| Molar mass | 101.193 g/mol |
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| Molecular weight | 101.193 u |
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| Chemical formula | C6H15N |
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| Monoisotopic mass | 101.120449 u |
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| CAS number | 121-44-8 |
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| PubChem CID | 8471 |
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How to calculate the molar mass of triethylamine
6 × 12.011 + 15 × 1.008 + 1 × 14.007 = 101.193 g/mol
- Count the atoms in C6H15N: C 6, H 15, N 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 101.193 g/mol.
Elemental composition of triethylamine
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 6 | 12.011 | 72.066 | 71.216% |
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| H Hydrogen | 15 | 1.008 | 15.12 | 14.942% |
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| N Nitrogen | 1 | 14.007 | 14.007 | 13.842% |
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Grams and moles of triethylamine
| Amount | Equals |
|---|
| 1 g | 0.0098821 mol |
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| 10 g | 0.098821 mol |
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| 100 g | 0.98821 mol |
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| 0.1 mol | 10.119 g |
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| 1 mol | 101.19 g |
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| 1 g, in particles | 5.9511 × 10^21 |
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Calculate other compounds