Tramadol at a glance
| Property | Value |
|---|
| Molar mass | 263.381 g/mol |
|---|
| Molecular weight | 263.381 u |
|---|
| Chemical formula | C16H25NO2 |
|---|
| Monoisotopic mass | 263.188529 u |
|---|
| CAS number | 27203-92-5 |
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| PubChem CID | 33741 |
|---|
How to calculate the molar mass of tramadol
16 × 12.011 + 25 × 1.008 + 1 × 14.007 + 2 × 15.999 = 263.381 g/mol
- Count the atoms in C16H25NO2: C 16, H 25, N 1, O 2.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 263.381 g/mol.
Elemental composition of tramadol
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 16 | 12.011 | 192.176 | 72.965% |
|---|
| H Hydrogen | 25 | 1.008 | 25.2 | 9.5679% |
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| N Nitrogen | 1 | 14.007 | 14.007 | 5.3182% |
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| O Oxygen | 2 | 15.999 | 31.998 | 12.149% |
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Grams and moles of tramadol
| Amount | Equals |
|---|
| 1 g | 0.0037968 mol |
|---|
| 10 g | 0.037968 mol |
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| 100 g | 0.37968 mol |
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| 0.1 mol | 26.338 g |
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| 1 mol | 263.38 g |
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| 1 g, in particles | 2.2865 × 10^21 |
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Calculate other compounds