tert-Butanol at a glance
| Property | Value |
|---|
| Molar mass | 74.123 g/mol |
|---|
| Molecular weight | 74.123 u |
|---|
| Chemical formula | (CH3)3COH |
|---|
| Monoisotopic mass | 74.0731649 u |
|---|
| CAS number | 75-65-0 |
|---|
| PubChem CID | 6386 |
|---|
How to calculate the molar mass of tert-Butanol
4 × 12.011 + 10 × 1.008 + 1 × 15.999 = 74.123 g/mol
- Count the atoms in (CH3)3COH: C 4, H 10, O 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 74.123 g/mol.
Elemental composition of tert-Butanol
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 4 | 12.011 | 48.044 | 64.817% |
|---|
| H Hydrogen | 10 | 1.008 | 10.08 | 13.599% |
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| O Oxygen | 1 | 15.999 | 15.999 | 21.584% |
|---|
Grams and moles of tert-Butanol
| Amount | Equals |
|---|
| 1 g | 0.013491 mol |
|---|
| 10 g | 0.13491 mol |
|---|
| 100 g | 1.3491 mol |
|---|
| 0.1 mol | 7.4123 g |
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| 1 mol | 74.123 g |
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| 1 g, in particles | 8.1245 × 10^21 |
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Calculate other compounds