Sodium Tetraborate at a glance
| Property | Value |
|---|
| Molar mass | 201.213 g/mol |
|---|
| Molecular weight | 201.213 u |
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| Chemical formula | Na2B4O7 |
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| Monoisotopic mass | 201.981162 u |
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| CAS number | 1330-43-4 |
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| PubChem CID | 10219853 |
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How to calculate the molar mass of sodium tetraborate
2 × 22.99 + 4 × 10.81 + 7 × 15.999 = 201.213 g/mol
- Count the atoms in Na2B4O7: Na 2, B 4, O 7.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 201.213 g/mol.
Elemental composition of sodium tetraborate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Na Sodium | 2 | 22.99 | 45.98 | 22.851% |
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| B Boron | 4 | 10.81 | 43.24 | 21.49% |
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| O Oxygen | 7 | 15.999 | 111.993 | 55.659% |
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Grams and moles of sodium tetraborate
| Amount | Equals |
|---|
| 1 g | 0.0049699 mol |
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| 10 g | 0.049699 mol |
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| 100 g | 0.49699 mol |
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| 0.1 mol | 20.121 g |
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| 1 mol | 201.21 g |
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| 1 g, in particles | 2.9929 × 10^21 |
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Calculate other compounds