Sodium Nitrate at a glance
| Property | Value |
|---|
| Molar mass | 84.994 g/mol |
|---|
| Molecular weight | 84.994 u |
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| Chemical formula | NaNO3 |
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| Monoisotopic mass | 84.9775871 u |
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| CAS number | 7631-99-4 |
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| PubChem CID | 24268 |
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How to calculate the molar mass of sodium nitrate
1 × 22.99 + 1 × 14.007 + 3 × 15.999 = 84.994 g/mol
- Count the atoms in NaNO3: Na 1, N 1, O 3.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 84.994 g/mol.
Elemental composition of sodium nitrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Na Sodium | 1 | 22.99 | 22.99 | 27.049% |
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| N Nitrogen | 1 | 14.007 | 14.007 | 16.48% |
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| O Oxygen | 3 | 15.999 | 47.997 | 56.471% |
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Grams and moles of sodium nitrate
| Amount | Equals |
|---|
| 1 g | 0.011766 mol |
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| 10 g | 0.11766 mol |
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| 100 g | 1.1766 mol |
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| 0.1 mol | 8.4994 g |
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| 1 mol | 84.994 g |
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| 1 g, in particles | 7.0854 × 10^21 |
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Calculate other compounds