Silver Nitrate at a glance
| Property | Value |
|---|
| Molar mass | 169.872 g/mol |
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| Molecular weight | 169.872 u |
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| Chemical formula | AgNO3 |
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| CAS number | 7761-88-8 |
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| PubChem CID | 24470 |
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How to calculate the molar mass of silver nitrate
1 × 107.868 + 1 × 14.007 + 3 × 15.999 = 169.872 g/mol
- Count the atoms in AgNO3: Ag 1, N 1, O 3.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 169.872 g/mol.
Elemental composition of silver nitrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Ag Silver | 1 | 107.868 | 107.868 | 63.5% |
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| N Nitrogen | 1 | 14.007 | 14.007 | 8.2456% |
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| O Oxygen | 3 | 15.999 | 47.997 | 28.255% |
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Grams and moles of silver nitrate
| Amount | Equals |
|---|
| 1 g | 0.0058868 mol |
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| 10 g | 0.058868 mol |
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| 100 g | 0.58868 mol |
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| 0.1 mol | 16.987 g |
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| 1 mol | 169.87 g |
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| 1 g, in particles | 3.5451 × 10^21 |
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Calculate other compounds