Salbutamol at a glance
| Property | Value |
|---|
| Molar mass | 239.315 g/mol |
|---|
| Molecular weight | 239.315 u |
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| Chemical formula | C13H21NO3 |
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| Monoisotopic mass | 239.152144 u |
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| CAS number | 18559-94-9 |
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| PubChem CID | 2083 |
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How to calculate the molar mass of salbutamol
13 × 12.011 + 21 × 1.008 + 1 × 14.007 + 3 × 15.999 = 239.315 g/mol
- Count the atoms in C13H21NO3: C 13, H 21, N 1, O 3.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 239.315 g/mol.
Elemental composition of salbutamol
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 13 | 12.011 | 156.143 | 65.246% |
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| H Hydrogen | 21 | 1.008 | 21.168 | 8.8452% |
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| N Nitrogen | 1 | 14.007 | 14.007 | 5.853% |
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| O Oxygen | 3 | 15.999 | 47.997 | 20.056% |
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Grams and moles of salbutamol
| Amount | Equals |
|---|
| 1 g | 0.0041786 mol |
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| 10 g | 0.041786 mol |
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| 100 g | 0.41786 mol |
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| 0.1 mol | 23.932 g |
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| 1 mol | 239.32 g |
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| 1 g, in particles | 2.5164 × 10^21 |
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Calculate other compounds