Magnesium Nitrate at a glance
| Property | Value |
|---|
| Molar mass | 148.313 g/mol |
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| Molecular weight | 148.313 u |
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| Chemical formula | Mg(NO3)2 |
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| Monoisotopic mass | 147.960677 u |
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| CAS number | 10377-60-3 |
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| PubChem CID | 25212 |
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How to calculate the molar mass of magnesium nitrate
1 × 24.305 + 2 × 14.007 + 6 × 15.999 = 148.313 g/mol
- Count the atoms in Mg(NO3)2: Mg 1, N 2, O 6.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 148.313 g/mol.
Elemental composition of magnesium nitrate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Mg Magnesium | 1 | 24.305 | 24.305 | 16.388% |
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| N Nitrogen | 2 | 14.007 | 28.014 | 18.888% |
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| O Oxygen | 6 | 15.999 | 95.994 | 64.724% |
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Grams and moles of magnesium nitrate
| Amount | Equals |
|---|
| 1 g | 0.0067425 mol |
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| 10 g | 0.067425 mol |
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| 100 g | 0.67425 mol |
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| 0.1 mol | 14.831 g |
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| 1 mol | 148.31 g |
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| 1 g, in particles | 4.0604 × 10^21 |
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Calculate other compounds