Magnesium Carbonate at a glance
| Property | Value |
|---|
| Molar mass | 84.313 g/mol |
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| Molecular weight | 84.313 u |
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| Chemical formula | MgCO3 |
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| Monoisotopic mass | 83.9697856 u |
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| CAS number | 546-93-0 |
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| PubChem CID | 11029 |
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How to calculate the molar mass of magnesium carbonate
1 × 24.305 + 1 × 12.011 + 3 × 15.999 = 84.313 g/mol
- Count the atoms in MgCO3: Mg 1, C 1, O 3.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 84.313 g/mol.
Elemental composition of magnesium carbonate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Mg Magnesium | 1 | 24.305 | 24.305 | 28.827% |
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| C Carbon | 1 | 12.011 | 12.011 | 14.246% |
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| O Oxygen | 3 | 15.999 | 47.997 | 56.927% |
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Grams and moles of magnesium carbonate
| Amount | Equals |
|---|
| 1 g | 0.011861 mol |
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| 10 g | 0.11861 mol |
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| 100 g | 1.1861 mol |
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| 0.1 mol | 8.4313 g |
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| 1 mol | 84.313 g |
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| 1 g, in particles | 7.1426 × 10^21 |
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Calculate other compounds