Lead(II) Acetate at a glance
| Property | Value |
|---|
| Molar mass | 325.088 g/mol |
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| Molecular weight | 325.088 u |
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| Chemical formula | Pb(CH3COO)2 |
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| CAS number | 301-04-2 |
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| PubChem CID | 9317 |
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How to calculate the molar mass of lead(II) acetate
1 × 207 + 4 × 12.011 + 6 × 1.008 + 4 × 15.999 = 325.088 g/mol
- Count the atoms in Pb(CH3COO)2: Pb 1, C 4, H 6, O 4.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 325.088 g/mol.
Elemental composition of lead(II) acetate
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| Pb Lead | 1 | 207 | 207 | 63.675% |
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| C Carbon | 4 | 12.011 | 48.044 | 14.779% |
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| H Hydrogen | 6 | 1.008 | 6.048 | 1.8604% |
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| O Oxygen | 4 | 15.999 | 63.996 | 19.686% |
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Grams and moles of lead(II) acetate
| Amount | Equals |
|---|
| 1 g | 0.0030761 mol |
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| 10 g | 0.030761 mol |
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| 100 g | 0.30761 mol |
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| 0.1 mol | 32.509 g |
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| 1 mol | 325.09 g |
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| 1 g, in particles | 1.8525 × 10^21 |
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Calculate other compounds