Isopropyl Alcohol at a glance
| Property | Value |
|---|
| Molar mass | 60.096 g/mol |
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| Molecular weight | 60.096 u |
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| Chemical formula | (CH3)2CHOH |
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| Monoisotopic mass | 60.0575149 u |
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| CAS number | 67-63-0 |
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| PubChem CID | 3776 |
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How to calculate the molar mass of isopropyl alcohol
3 × 12.011 + 8 × 1.008 + 1 × 15.999 = 60.096 g/mol
- Count the atoms in (CH3)2CHOH: C 3, H 8, O 1.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 60.096 g/mol.
Elemental composition of isopropyl alcohol
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 3 | 12.011 | 36.033 | 59.959% |
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| H Hydrogen | 8 | 1.008 | 8.064 | 13.419% |
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| O Oxygen | 1 | 15.999 | 15.999 | 26.622% |
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Grams and moles of isopropyl alcohol
| Amount | Equals |
|---|
| 1 g | 0.01664 mol |
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| 10 g | 0.1664 mol |
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| 100 g | 1.664 mol |
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| 0.1 mol | 6.0096 g |
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| 1 mol | 60.096 g |
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| 1 g, in particles | 1.0021 × 10^22 |
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Calculate other compounds