Imidazole at a glance
| Property | Value |
|---|
| Molar mass | 68.079 g/mol |
|---|
| Molecular weight | 68.079 u |
|---|
| Chemical formula | C3H4N2 |
|---|
| Monoisotopic mass | 68.0374481 u |
|---|
| CAS number | 288-32-4 |
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| PubChem CID | 795 |
|---|
How to calculate the molar mass of imidazole
3 × 12.011 + 4 × 1.008 + 2 × 14.007 = 68.079 g/mol
- Count the atoms in C3H4N2: C 3, H 4, N 2.
- Multiply each atom count by the atomic weight of the element.
- Add the results to get 68.079 g/mol.
Elemental composition of imidazole
| Element | Atoms | Atomic weight | Mass (g/mol) | Mass % |
|---|
| C Carbon | 3 | 12.011 | 36.033 | 52.928% |
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| H Hydrogen | 4 | 1.008 | 4.032 | 5.9225% |
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| N Nitrogen | 2 | 14.007 | 28.014 | 41.149% |
|---|
Grams and moles of imidazole
| Amount | Equals |
|---|
| 1 g | 0.014689 mol |
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| 10 g | 0.14689 mol |
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| 100 g | 1.4689 mol |
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| 0.1 mol | 6.8079 g |
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| 1 mol | 68.079 g |
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| 1 g, in particles | 8.8458 × 10^21 |
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Calculate other compounds